Displacement Vector Calculator
📍 Initial Position (Start)
🎯 Final Position (End)
💡 Quick Examples:
📊 Visual Representation
📊 Displacement Vector Results
📋 Additional Properties
🔄 Displacement vs Distance
📐 Displacement (Vector)
- • Straight-line distance from start to end
- • Has both magnitude AND direction
- • Can be zero if you return to start
- • Independent of path taken
📏 Distance (Scalar)
- • Total path length traveled
- • Has magnitude only (no direction)
- • Always positive or zero
- • Depends on actual path taken
Displacement Vector Calculator - Calculate Distance & Direction
📐 Calculate displacement vector, magnitude, direction angle, and components. Visualize motion in 2D and 3D space with step-by-step explanations.
What is Displacement?
Displacement is a vector quantity that represents the change in position of an object. It's the straight-line distance from the initial position to the final position, regardless of the actual path taken.
Displacement Formula
2D Displacement:
Δr = ⟨Δx, Δy⟩ = ⟨x₁ - x₀, y₁ - y₀⟩
3D Displacement:
Δr = ⟨Δx, Δy, Δz⟩ = ⟨x₁ - x₀, y₁ - y₀, z₁ - z₀⟩
Magnitude (Distance)
2D:
|Δr| = √(Δx² + Δy²)
3D:
|Δr| = √(Δx² + Δy² + Δz²)
Direction Angle
2D Angle from X-axis:
θ = arctan(Δy/Δx)
- Measured counterclockwise from positive X-axis
- Range: -180° to +180° (or 0° to 360°)
- Use atan2(Δy, Δx) for correct quadrant
Unit Vector
Unit vector has magnitude of 1 and points in the direction of displacement:
û = Δr / |Δr|
Calculation Examples
Example 1: Horizontal Motion
- Initial: (0, 0), Final: (10, 0)
- Displacement: ⟨10, 0⟩ m
- Magnitude: 10 m
- Direction: 0° (East)
Example 2: Diagonal Motion
- Initial: (2, 1), Final: (7, 5)
- Displacement: ⟨5, 4⟩ m
- Magnitude: √(5² + 4²) = 6.40 m
- Direction: arctan(4/5) = 38.66°
Example 3: 3D Motion
- Initial: (1, 2, 3), Final: (4, 6, 8)
- Displacement: ⟨3, 4, 5⟩ m
- Magnitude: √(3² + 4² + 5²) = 7.07 m
Displacement vs Distance
Key Differences:
- Displacement: Vector (magnitude + direction), straight-line, can be zero
- Distance: Scalar (magnitude only), total path, always positive
Example: If you walk 5m East, then 5m West:
- Distance traveled: 10 m
- Displacement: 0 m (back at start)
Real-World Applications
- Navigation: GPS calculates displacement to destination
- Physics: Velocity = displacement / time
- Engineering: Structural deformation analysis
- Robotics: Path planning and position tracking
- Sports: Analyzing player movement on field
- Aviation: Flight paths and navigation
Compass Directions
- N (North): 90° (positive Y-axis)
- E (East): 0° (positive X-axis)
- S (South): -90° or 270° (negative Y-axis)
- W (West): ±180° (negative X-axis)
- NE: 45°, SE: -45°, SW: -135°, NW: 135°
Vector Addition
Multiple displacements can be added:
Δr_total = Δr₁ + Δr₂ + Δr₃ + ...
Example: Walk 3m East, then 4m North
- Δr₁ = ⟨3, 0⟩, Δr₂ = ⟨0, 4⟩
- Total: ⟨3, 4⟩, Magnitude: 5m, Direction: 53.13° (NE)
Important Properties
- Displacement magnitude ≤ Distance traveled (equality only for straight path)
- Displacement can be negative (components can be negative)
- Zero displacement ≠ no motion (you can return to start)
- Displacement is path-independent (only start and end matter)
Common Mistakes
- Confusing displacement with distance - they're different!
- Wrong angle quadrant - use atan2 function for correct angle
- Forgetting direction - displacement is a vector, must have direction
- Adding scalars to vectors - can't add distance to displacement
💡 Pro Tip: When solving physics problems, always draw a diagram showing initial and final positions. Use the right-hand rule for 3D problems: thumb (X), index finger (Y), middle finger (Z). Remember that displacement depends ONLY on start and end points, not the path taken - this is why a person walking in a circle has zero displacement despite traveling a large distance!
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